6c=2(-c+12)

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Solution for 6c=2(-c+12) equation: 



6c=2(-c+12)

We move all terms to the left:

6c-(2(-c+12))=0

We add all the numbers together, and all the variables

6c-(2(-1c+12))=0



We calculate terms in parentheses: -(2(-1c+12)), so:

2(-1c+12)

We multiply parentheses

-2c+24

Back to the equation:

-(-2c+24)



We get rid of parentheses

6c+2c-24=0

We add all the numbers together, and all the variables

8c-24=0

We move all terms containing c to the left, all other terms to the right

8c=24

c=24/8

c=3

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