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6c=5(1-c)-3
We move all terms to the left:
6c-(5(1-c)-3)=0
We add all the numbers together, and all the variables
6c-(5(-1c+1)-3)=0
We calculate terms in parentheses: -(5(-1c+1)-3), so:We get rid of parentheses
5(-1c+1)-3
We multiply parentheses
-5c+5-3
We add all the numbers together, and all the variables
-5c+2
Back to the equation:
-(-5c+2)
6c+5c-2=0
We add all the numbers together, and all the variables
11c-2=0
We move all terms containing c to the left, all other terms to the right
11c=2
c=2/11
c=2/11
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