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6d(d-5)=0
We multiply parentheses
6d^2-30d=0
a = 6; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·6·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*6}=\frac{0}{12} =0 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*6}=\frac{60}{12} =5 $
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