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6d+15=1/2d-29
We move all terms to the left:
6d+15-(1/2d-29)=0
Domain of the equation: 2d-29)!=0We get rid of parentheses
d∈R
6d-1/2d+29+15=0
We multiply all the terms by the denominator
6d*2d+29*2d+15*2d-1=0
Wy multiply elements
12d^2+58d+30d-1=0
We add all the numbers together, and all the variables
12d^2+88d-1=0
a = 12; b = 88; c = -1;
Δ = b2-4ac
Δ = 882-4·12·(-1)
Δ = 7792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7792}=\sqrt{16*487}=\sqrt{16}*\sqrt{487}=4\sqrt{487}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-4\sqrt{487}}{2*12}=\frac{-88-4\sqrt{487}}{24} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+4\sqrt{487}}{2*12}=\frac{-88+4\sqrt{487}}{24} $
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