6d-1/2(2d-8)=-5/4(d+8)

Solution for 6d-1/2(2d-8)=-5/4(d+8) equation:

6d-1/2(2d-8)=-5/4(d+8)

We move all terms to the left:

6d-1/2(2d-8)-(-5/4(d+8))=0


Domain of the equation: 2(2d-8)!=0

d∈R



Domain of the equation: 4(d+8))!=0

d∈R


We calculate fractions


6d+(-4dd/(2(2d-8)*4(d+8)))+(-(-10d2)/(2(2d-8)*4(d+8)))=0


We calculate terms in parentheses: +(-4dd/(2(2d-8)*4(d+8))), so:

-4dd/(2(2d-8)*4(d+8))

We multiply all the terms by the denominator


-4dd

Back to the equation:

+(-4dd)



We calculate terms in parentheses: +(-(-10d2)/(2(2d-8)*4(d+8))), so:

-(-10d2)/(2(2d-8)*4(d+8))

We add all the numbers together, and all the variables

-(-10d^2)/(2(2d-8)*4(d+8))

We multiply all the terms by the denominator


-(-10d^2)

We get rid of parentheses

10d^2

Back to the equation:

+(10d^2)


determiningTheFunctionDomain
10d^2+6d+(-4dd)=0

We get rid of parentheses

10d^2+6d-4dd=0