6e+13=(3e-10)/2

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Solution for 6e+13=(3e-10)/2 equation: 



6e+13=(3e-10)/2

We move all terms to the left:

6e+13-((3e-10)/2)=0

We multiply all the terms by the denominator


6e*2)-((3e-10)+13*2)=0

We add all the numbers together, and all the variables

6e*2)-((3e-10)=0

Wy multiply elements

12e^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$e=\frac{-b}{2a}=\frac{0}{24}=0$

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