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6f^2+33f-63=0
a = 6; b = 33; c = -63;
Δ = b2-4ac
Δ = 332-4·6·(-63)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-51}{2*6}=\frac{-84}{12} =-7 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+51}{2*6}=\frac{18}{12} =1+1/2 $
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