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6g(2g-1)=13g
We move all terms to the left:
6g(2g-1)-(13g)=0
We add all the numbers together, and all the variables
-13g+6g(2g-1)=0
We multiply parentheses
12g^2-13g-6g=0
We add all the numbers together, and all the variables
12g^2-19g=0
a = 12; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·12·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*12}=\frac{0}{24} =0 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*12}=\frac{38}{24} =1+7/12 $
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