6g+2(-6+3g)=1+g

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Solution for 6g+2(-6+3g)=1+g equation:



6g+2(-6+3g)=1+g
We move all terms to the left:
6g+2(-6+3g)-(1+g)=0
We add all the numbers together, and all the variables
6g+2(3g-6)-(g+1)=0
We multiply parentheses
6g+6g-(g+1)-12=0
We get rid of parentheses
6g+6g-g-1-12=0
We add all the numbers together, and all the variables
11g-13=0
We move all terms containing g to the left, all other terms to the right
11g=13
g=13/11
g=1+2/11

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