6g+2(-6+3g)=1+g

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Solution for 6g+2(-6+3g)=1+g equation: 



6g+2(-6+3g)=1+g

We move all terms to the left:

6g+2(-6+3g)-(1+g)=0

We add all the numbers together, and all the variables

6g+2(3g-6)-(g+1)=0

We multiply parentheses

6g+6g-(g+1)-12=0

We get rid of parentheses

6g+6g-g-1-12=0

We add all the numbers together, and all the variables

11g-13=0

We move all terms containing g to the left, all other terms to the right

11g=13

g=13/11

g=1+2/11

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