6g+2(-7+2g)=1+g

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Solution for 6g+2(-7+2g)=1+g equation: 



6g+2(-7+2g)=1+g

We move all terms to the left:

6g+2(-7+2g)-(1+g)=0

We add all the numbers together, and all the variables

6g+2(2g-7)-(g+1)=0

We multiply parentheses

6g+4g-(g+1)-14=0

We get rid of parentheses

6g+4g-g-1-14=0

We add all the numbers together, and all the variables

9g-15=0

We move all terms containing g to the left, all other terms to the right

9g=15

g=15/9

g=1+2/3

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