6h(9-3h)=6-3(h+2)

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Solution for 6h(9-3h)=6-3(h+2) equation:



6h(9-3h)=6-3(h+2)
We move all terms to the left:
6h(9-3h)-(6-3(h+2))=0
We add all the numbers together, and all the variables
6h(-3h+9)-(6-3(h+2))=0
We multiply parentheses
-18h^2+54h-(6-3(h+2))=0
We calculate terms in parentheses: -(6-3(h+2)), so:
6-3(h+2)
determiningTheFunctionDomain -3(h+2)+6
We multiply parentheses
-3h-6+6
We add all the numbers together, and all the variables
-3h
Back to the equation:
-(-3h)
We get rid of parentheses
-18h^2+54h+3h=0
We add all the numbers together, and all the variables
-18h^2+57h=0
a = -18; b = 57; c = 0;
Δ = b2-4ac
Δ = 572-4·(-18)·0
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-57}{2*-18}=\frac{-114}{-36} =3+1/6 $
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+57}{2*-18}=\frac{0}{-36} =0 $

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