6h(9-3h)=6-3(h+2)

Solution for 6h(9-3h)=6-3(h+2) equation:

6h(9-3h)=6-3(h+2)

We move all terms to the left:

6h(9-3h)-(6-3(h+2))=0

We add all the numbers together, and all the variables

6h(-3h+9)-(6-3(h+2))=0

We multiply parentheses

-18h^2+54h-(6-3(h+2))=0


We calculate terms in parentheses: -(6-3(h+2)), so:

6-3(h+2)

determiningTheFunctionDomain
-3(h+2)+6

We multiply parentheses

-3h-6+6

We add all the numbers together, and all the variables

-3h

Back to the equation:

-(-3h)


We get rid of parentheses

-18h^2+54h+3h=0

We add all the numbers together, and all the variables

-18h^2+57h=0

a = -18; b = 57; c = 0;
Δ = b2-4ac
Δ = 572-4·(-18)·0
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-57}{2*-18}=\frac{-114}{-36}
=3+1/6
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+57}{2*-18}=\frac{0}{-36}
=0
$