6h/(9-3h)=6-3(h+2)

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Solution for 6h/(9-3h)=6-3(h+2) equation: 



6h/(9-3h)=6-3(h+2)

We move all terms to the left:

6h/(9-3h)-(6-3(h+2))=0



Domain of the equation: (9-3h)!=0

We move all terms containing h to the left, all other terms to the right

-3h!=-9

h!=-9/-3

h!=+3

h∈R



We add all the numbers together, and all the variables

6h/(-3h+9)-(6-3(h+2))=0

We multiply all the terms by the denominator


6h-((6-3(h+2)))*(-3h+9)=0



We calculate terms in parentheses: -((6-3(h+2)))*(-3h+9), so:

(6-3(h+2)))*(-3h+9

We add all the numbers together, and all the variables

-3h+(6-3(h+2)))*(+9

Back to the equation:

-(-3h+(6-3(h+2)))*(+9)



We add all the numbers together, and all the variables

6h-(-3h+(6-3(h+2)))*9=0

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