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6i(3-9i)=0
We add all the numbers together, and all the variables
6i(-9i+3)=0
We multiply parentheses
-54i^2+18i=0
a = -54; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-54)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-54}=\frac{-36}{-108} =1/3 $$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-54}=\frac{0}{-108} =0 $
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