6j2=486

Solution for 6j2=486 equation:

6j^2=486

We move all terms to the left:

6j^2-(486)=0

a = 6; b = 0; c = -486;
Δ = b2-4ac
Δ = 02-4·6·(-486)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*6}=\frac{-108}{12}
=-9
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*6}=\frac{108}{12}
=9
$