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6k(k+4)=5k-15
We move all terms to the left:
6k(k+4)-(5k-15)=0
We multiply parentheses
6k^2+24k-(5k-15)=0
We get rid of parentheses
6k^2+24k-5k+15=0
We add all the numbers together, and all the variables
6k^2+19k+15=0
a = 6; b = 19; c = +15;
Δ = b2-4ac
Δ = 192-4·6·15
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:k_{1}=\frac{-b-\sqrt{\Delta}}{2a}k_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{1}=1k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-1}{2*6}=\frac{-20}{12} =-1+2/3k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+1}{2*6}=\frac{-18}{12} =-1+1/2
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