6k+(3*10-8)=(2*2)k+22

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Solution for 6k+(3*10-8)=(2*2)k+22 equation: 



6k+(3*10-8)=(2*2)k+22

We move all terms to the left:

6k+(3*10-8)-((2*2)k+22)=0

We add all the numbers together, and all the variables

6k-(4k+22)+22=0

We get rid of parentheses

6k-4k-22+22=0

We add all the numbers together, and all the variables

2k=0

k=0/2

k=0

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