6k+(3*10-8)=(2*2*2)k+22

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Solution for 6k+(3*10-8)=(2*2*2)k+22 equation:



6k+(3*10-8)=(2*2*2)k+22
We move all terms to the left:
6k+(3*10-8)-((2*2*2)k+22)=0
We add all the numbers together, and all the variables
6k-(8k+22)+22=0
We get rid of parentheses
6k-8k-22+22=0
We add all the numbers together, and all the variables
-2k=0
k=0/-2
k=0

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