6k+(3/10-8)=(2/3)K+22

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Solution for 6k+(3/10-8)=(2/3)K+22 equation: 


x in (-oo:+oo)

6*k+3/10-8 = (2/3)*K+22 // - (2/3)*K+22

6*k-((2/3)*K)+3/10-22-8 = 0

(-2/3)*K+6*k+3/10-22-8 = 0

6*k-2/3*K-297/10 = 0

x naleu017Cy do R

x in (-oo:+oo)

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