6k-3(k+2)=3(k-2)

Solution for 6k-3(k+2)=3(k-2) equation:

Simplifying
6k + -3(k + 2) = 3(k + -2)

Reorder the terms:
6k + -3(2 + k) = 3(k + -2)
6k + (2 * -3 + k * -3) = 3(k + -2)
6k + (-6 + -3k) = 3(k + -2)

Reorder the terms:
-6 + 6k + -3k = 3(k + -2)

Combine like terms: 6k + -3k = 3k
-6 + 3k = 3(k + -2)

Reorder the terms:
-6 + 3k = 3(-2 + k)
-6 + 3k = (-2 * 3 + k * 3)
-6 + 3k = (-6 + 3k)

Add '6' to each side of the equation.
-6 + 6 + 3k = -6 + 6 + 3k

Combine like terms: -6 + 6 = 0
0 + 3k = -6 + 6 + 3k
3k = -6 + 6 + 3k

Combine like terms: -6 + 6 = 0
3k = 0 + 3k
3k = 3k

Add '-3k' to each side of the equation.
3k + -3k = 3k + -3k

Combine like terms: 3k + -3k = 0
0 = 3k + -3k

Combine like terms: 3k + -3k = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.