6k2+13k+7=0

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Solution for 6k2+13k+7=0 equation: 



6k^2+13k+7=0

a = 6; b = 13; c = +7;
Δ = b2-4ac
Δ = 132-4·6·7
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-1}{2*6}=\frac{-14}{12}
=-1+1/6
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+1}{2*6}=\frac{-12}{12}
=-1
$

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