6k2=26

Solution for 6k2=26 equation:

6k^2=26

We move all terms to the left:

6k^2-(26)=0

a = 6; b = 0; c = -26;
Δ = b2-4ac
Δ = 02-4·6·(-26)
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{39}}{2*6}=\frac{0-4\sqrt{39}}{12}
=-\frac{4\sqrt{39}}{12}
=-\frac{\sqrt{39}}{3}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{39}}{2*6}=\frac{0+4\sqrt{39}}{12}
=\frac{4\sqrt{39}}{12}
=\frac{\sqrt{39}}{3}
$