6m(3m+3)=0

Solution for 6m(3m+3)=0 equation:

6m(3m+3)=0

We multiply parentheses

18m^2+18m=0

a = 18; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·18·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*18}=\frac{-36}{36}
=-1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*18}=\frac{0}{36}
=0
$