6m(m+4)=m+15

Solution for 6m(m+4)=m+15 equation:

6m(m+4)=m+15

We move all terms to the left:

6m(m+4)-(m+15)=0

We multiply parentheses

6m^2+24m-(m+15)=0

We get rid of parentheses

6m^2+24m-m-15=0

We add all the numbers together, and all the variables

6m^2+23m-15=0

a = 6; b = 23; c = -15;
Δ = b2-4ac
Δ = 232-4·6·(-15)
Δ = 889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{889}}{2*6}=\frac{-23-\sqrt{889}}{12}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{889}}{2*6}=\frac{-23+\sqrt{889}}{12}
$