6m(m-3)+4(2+2m)=

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Solution for 6m(m-3)+4(2+2m)= equation:


Simplifying
6m(m + -3) + 4(2 + 2m) = 0

Reorder the terms:
6m(-3 + m) + 4(2 + 2m) = 0
(-3 * 6m + m * 6m) + 4(2 + 2m) = 0
(-18m + 6m2) + 4(2 + 2m) = 0
-18m + 6m2 + (2 * 4 + 2m * 4) = 0
-18m + 6m2 + (8 + 8m) = 0

Reorder the terms:
8 + -18m + 8m + 6m2 = 0

Combine like terms: -18m + 8m = -10m
8 + -10m + 6m2 = 0

Solving
8 + -10m + 6m2 = 0

Solving for variable 'm'.

Factor out the Greatest Common Factor (GCF), '2'.
2(4 + -5m + 3m2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(4 + -5m + 3m2)' equal to zero and attempt to solve: Simplifying 4 + -5m + 3m2 = 0 Solving 4 + -5m + 3m2 = 0 Begin completing the square. Divide all terms by 3 the coefficient of the squared term: Divide each side by '3'. 1.333333333 + -1.666666667m + m2 = 0 Move the constant term to the right: Add '-1.333333333' to each side of the equation. 1.333333333 + -1.666666667m + -1.333333333 + m2 = 0 + -1.333333333 Reorder the terms: 1.333333333 + -1.333333333 + -1.666666667m + m2 = 0 + -1.333333333 Combine like terms: 1.333333333 + -1.333333333 = 0.000000000 0.000000000 + -1.666666667m + m2 = 0 + -1.333333333 -1.666666667m + m2 = 0 + -1.333333333 Combine like terms: 0 + -1.333333333 = -1.333333333 -1.666666667m + m2 = -1.333333333 The m term is -1.666666667m. Take half its coefficient (-0.8333333335). Square it (0.6944444447) and add it to both sides. Add '0.6944444447' to each side of the equation. -1.666666667m + 0.6944444447 + m2 = -1.333333333 + 0.6944444447 Reorder the terms: 0.6944444447 + -1.666666667m + m2 = -1.333333333 + 0.6944444447 Combine like terms: -1.333333333 + 0.6944444447 = -0.6388888883 0.6944444447 + -1.666666667m + m2 = -0.6388888883 Factor a perfect square on the left side: (m + -0.8333333335)(m + -0.8333333335) = -0.6388888883 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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