6m+2(m+1)+3=4(m+2)-4

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Solution for 6m+2(m+1)+3=4(m+2)-4 equation: 



6m+2(m+1)+3=4(m+2)-4

We move all terms to the left:

6m+2(m+1)+3-(4(m+2)-4)=0

We multiply parentheses

6m+2m-(4(m+2)-4)+2+3=0



We calculate terms in parentheses: -(4(m+2)-4), so:

4(m+2)-4

We multiply parentheses

4m+8-4

We add all the numbers together, and all the variables

4m+4

Back to the equation:

-(4m+4)



We add all the numbers together, and all the variables

8m-(4m+4)+5=0

We get rid of parentheses

8m-4m-4+5=0

We add all the numbers together, and all the variables

4m+1=0

We move all terms containing m to the left, all other terms to the right

4m=-1

m=-1/4

m=-1/4

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