6m+3=(2m-4)/2

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Solution for 6m+3=(2m-4)/2 equation: 



6m+3=(2m-4)/2

We move all terms to the left:

6m+3-((2m-4)/2)=0

We multiply all the terms by the denominator


6m*2)-((2m-4)+3*2)=0

We add all the numbers together, and all the variables

6m*2)-((2m-4)=0

Wy multiply elements

12m^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{24}=0$

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