6m+4(4m+1)=2(2+m)+7m

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Solution for 6m+4(4m+1)=2(2+m)+7m equation: 



6m+4(4m+1)=2(2+m)+7m

We move all terms to the left:

6m+4(4m+1)-(2(2+m)+7m)=0

We add all the numbers together, and all the variables

6m+4(4m+1)-(2(m+2)+7m)=0

We multiply parentheses

6m+16m-(2(m+2)+7m)+4=0



We calculate terms in parentheses: -(2(m+2)+7m), so:

2(m+2)+7m

We add all the numbers together, and all the variables

7m+2(m+2)

We multiply parentheses

7m+2m+4

We add all the numbers together, and all the variables

9m+4

Back to the equation:

-(9m+4)



We add all the numbers together, and all the variables

22m-(9m+4)+4=0

We get rid of parentheses

22m-9m-4+4=0

We add all the numbers together, and all the variables

13m=0

m=0/13

m=0

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