6m+4-5m+2+m=3(1m+1)

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Solution for 6m+4-5m+2+m=3(1m+1) equation: 



6m+4-5m+2+m=3(1m+1)

We move all terms to the left:

6m+4-5m+2+m-(3(1m+1))=0

We add all the numbers together, and all the variables

6m-5m+m-(3(m+1))+4+2=0

We add all the numbers together, and all the variables

2m-(3(m+1))+6=0



We calculate terms in parentheses: -(3(m+1)), so:

3(m+1)

We multiply parentheses

3m+3

Back to the equation:

-(3m+3)



We get rid of parentheses

2m-3m-3+6=0

We add all the numbers together, and all the variables

-1m+3=0

We move all terms containing m to the left, all other terms to the right

-m=-3

m=-3/-1

m=+3

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