6m+7=m2+5m-1

Solution for 6m+7=m2+5m-1 equation:

6m+7=m2+5m-1

We move all terms to the left:

6m+7-(m2+5m-1)=0

We add all the numbers together, and all the variables

-(+m^2+5m-1)+6m+7=0

We get rid of parentheses

-m^2-5m+6m+1+7=0

We add all the numbers together, and all the variables

-1m^2+m+8=0

a = -1; b = 1; c = +8;
Δ = b2-4ac
Δ = 12-4·(-1)·8
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{33}}{2*-1}=\frac{-1-\sqrt{33}}{-2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{33}}{2*-1}=\frac{-1+\sqrt{33}}{-2}
$