6m-3+2m+9=4(m+3)+12

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Solution for 6m-3+2m+9=4(m+3)+12 equation:



6m-3+2m+9=4(m+3)+12
We move all terms to the left:
6m-3+2m+9-(4(m+3)+12)=0
We add all the numbers together, and all the variables
8m-(4(m+3)+12)+6=0
We calculate terms in parentheses: -(4(m+3)+12), so:
4(m+3)+12
We multiply parentheses
4m+12+12
We add all the numbers together, and all the variables
4m+24
Back to the equation:
-(4m+24)
We get rid of parentheses
8m-4m-24+6=0
We add all the numbers together, and all the variables
4m-18=0
We move all terms containing m to the left, all other terms to the right
4m=18
m=18/4
m=4+1/2

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