6m2+42m+8=8

Solution for 6m2+42m+8=8 equation:

6m^2+42m+8=8

We move all terms to the left:

6m^2+42m+8-(8)=0

We add all the numbers together, and all the variables

6m^2+42m=0

a = 6; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·6·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*6}=\frac{-84}{12}
=-7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*6}=\frac{0}{12}
=0
$