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6m^2+5m-116=0
a = 6; b = 5; c = -116;
Δ = b2-4ac
Δ = 52-4·6·(-116)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-53}{2*6}=\frac{-58}{12} =-4+5/6 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+53}{2*6}=\frac{48}{12} =4 $
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