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6m^2+66m=-180
We move all terms to the left:
6m^2+66m-(-180)=0
We add all the numbers together, and all the variables
6m^2+66m+180=0
a = 6; b = 66; c = +180;
Δ = b2-4ac
Δ = 662-4·6·180
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-6}{2*6}=\frac{-72}{12} =-6 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+6}{2*6}=\frac{-60}{12} =-5 $
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