6m2+m-82=10

Solution for 6m2+m-82=10 equation:

6m^2+m-82=10

We move all terms to the left:

6m^2+m-82-(10)=0

We add all the numbers together, and all the variables

6m^2+m-92=0

a = 6; b = 1; c = -92;
Δ = b2-4ac
Δ = 12-4·6·(-92)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-47}{2*6}=\frac{-48}{12}
=-4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+47}{2*6}=\frac{46}{12}
=3+5/6
$