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6m^2=-5+31m
We move all terms to the left:
6m^2-(-5+31m)=0
We add all the numbers together, and all the variables
6m^2-(31m-5)=0
We get rid of parentheses
6m^2-31m+5=0
a = 6; b = -31; c = +5;
Δ = b2-4ac
Δ = -312-4·6·5
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-29}{2*6}=\frac{2}{12} =1/6 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+29}{2*6}=\frac{60}{12} =5 $
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