6n(n+8)=0

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Solution for 6n(n+8)=0 equation:



6n(n+8)=0
We multiply parentheses
6n^2+48n=0
a = 6; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·6·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*6}=\frac{-96}{12} =-8 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*6}=\frac{0}{12} =0 $

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