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6n(n+8)=0
We multiply parentheses
6n^2+48n=0
a = 6; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·6·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*6}=\frac{-96}{12} =-8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*6}=\frac{0}{12} =0 $
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