6n+3-5(4-n)=27

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Solution for 6n+3-5(4-n)=27 equation: 



6n+3-5(4-n)=27

We move all terms to the left:

6n+3-5(4-n)-(27)=0

We add all the numbers together, and all the variables

6n-5(-1n+4)+3-27=0

We add all the numbers together, and all the variables

6n-5(-1n+4)-24=0

We multiply parentheses

6n+5n-20-24=0

We add all the numbers together, and all the variables

11n-44=0

We move all terms containing n to the left, all other terms to the right

11n=44

n=44/11

n=4

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