6n-2(2n-7)=-2(n-3)-2n

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Solution for 6n-2(2n-7)=-2(n-3)-2n equation: 



6n-2(2n-7)=-2(n-3)-2n

We move all terms to the left:

6n-2(2n-7)-(-2(n-3)-2n)=0

We multiply parentheses

6n-4n-(-2(n-3)-2n)+14=0



We calculate terms in parentheses: -(-2(n-3)-2n), so:

-2(n-3)-2n

We add all the numbers together, and all the variables

-2n-2(n-3)

We multiply parentheses

-2n-2n+6

We add all the numbers together, and all the variables

-4n+6

Back to the equation:

-(-4n+6)



We add all the numbers together, and all the variables

2n-(-4n+6)+14=0

We get rid of parentheses

2n+4n-6+14=0

We add all the numbers together, and all the variables

6n+8=0

We move all terms containing n to the left, all other terms to the right

6n=-8

n=-8/6

n=-1+1/3

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