6n-7(1+2n)=5(-2n-3)-2

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Solution for 6n-7(1+2n)=5(-2n-3)-2 equation: 



6n-7(1+2n)=5(-2n-3)-2

We move all terms to the left:

6n-7(1+2n)-(5(-2n-3)-2)=0

We add all the numbers together, and all the variables

6n-7(2n+1)-(5(-2n-3)-2)=0

We multiply parentheses

6n-14n-(5(-2n-3)-2)-7=0



We calculate terms in parentheses: -(5(-2n-3)-2), so:

5(-2n-3)-2

We multiply parentheses

-10n-15-2

We add all the numbers together, and all the variables

-10n-17

Back to the equation:

-(-10n-17)



We add all the numbers together, and all the variables

-8n-(-10n-17)-7=0

We get rid of parentheses

-8n+10n+17-7=0

We add all the numbers together, and all the variables

2n+10=0

We move all terms containing n to the left, all other terms to the right

2n=-10

n=-10/2

n=-5

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