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6n^2+-13n+6=0
We add all the numbers together, and all the variables
6n^2-13n=0
a = 6; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·6·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*6}=\frac{0}{12} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*6}=\frac{26}{12} =2+1/6 $
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