If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6n^2+12n-48=0
a = 6; b = 12; c = -48;
Δ = b2-4ac
Δ = 122-4·6·(-48)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-36}{2*6}=\frac{-48}{12} =-4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+36}{2*6}=\frac{24}{12} =2 $
| 6(r+7)=132 | | f/2+3=6 | | 5x2+20x-69=-9 | | 13-2k=-7 | | 7t-8=-3t+10+7t | | 6c+12.50=71 | | 0.2x+0.11=0.71 | | 4x-1+3x+6=2x+9+4x | | 2p2-3p-3=0 | | 4x-1+3x+6=2x | | −8+6m=12(−4m+16) | | j/3-9=-7 | | -1.6=w/8+11.2 | | 4d+13=35 | | 0.7(7x+14=1.2-(x+2) | | 4x-x=4x-25 | | 2x+52=82 | | 8y+4(3+y)=3(y-4)+10y | | -6c+11=17 | | 7c=7c+3= | | -3+3n=-12 | | 1/2x+9=-31 | | g+(-5)=15 | | -10-3z=8+3z | | 2x+41+7x-59=180 | | j/4-5=9 | | x+3/2-2=20 | | (5p-7)=(9p-13) | | 4-6b=-14 | | 15(y+1)=60 | | -4(4+10)-6=3(x-2) | | 4a+10=6a+30 |