6n2+8n=128

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Solution for 6n2+8n=128 equation:



6n^2+8n=128
We move all terms to the left:
6n^2+8n-(128)=0
a = 6; b = 8; c = -128;
Δ = b2-4ac
Δ = 82-4·6·(-128)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-56}{2*6}=\frac{-64}{12} =-5+1/3 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+56}{2*6}=\frac{48}{12} =4 $

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