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6n^2-5n-14=0
a = 6; b = -5; c = -14;
Δ = b2-4ac
Δ = -52-4·6·(-14)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-19}{2*6}=\frac{-14}{12} =-1+1/6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+19}{2*6}=\frac{24}{12} =2 $
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