6p+(5p+5)=-8-2(1p+12)

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Solution for 6p+(5p+5)=-8-2(1p+12) equation: 



6p+(5p+5)=-8-2(1p+12)

We move all terms to the left:

6p+(5p+5)-(-8-2(1p+12))=0

We add all the numbers together, and all the variables

6p+(5p+5)-(-8-2(p+12))=0

We get rid of parentheses

6p+5p-(-8-2(p+12))+5=0



We calculate terms in parentheses: -(-8-2(p+12)), so:

-8-2(p+12)

determiningTheFunctionDomain
-2(p+12)-8

We multiply parentheses

-2p-24-8

We add all the numbers together, and all the variables

-2p-32

Back to the equation:

-(-2p-32)



We add all the numbers together, and all the variables

11p-(-2p-32)+5=0

We get rid of parentheses

11p+2p+32+5=0

We add all the numbers together, and all the variables

13p+37=0

We move all terms containing p to the left, all other terms to the right

13p=-37

p=-37/13

p=-2+11/13

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