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6p+3=2/3p
We move all terms to the left:
6p+3-(2/3p)=0
Domain of the equation: 3p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
6p-(+2/3p)+3=0
We get rid of parentheses
6p-2/3p+3=0
We multiply all the terms by the denominator
6p*3p+3*3p-2=0
Wy multiply elements
18p^2+9p-2=0
a = 18; b = 9; c = -2;
Δ = b2-4ac
Δ = 92-4·18·(-2)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-15}{2*18}=\frac{-24}{36} =-2/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+15}{2*18}=\frac{6}{36} =1/6 $
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