6p+4(1-p)=10p+2(1-p)

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Solution for 6p+4(1-p)=10p+2(1-p) equation: 



6p+4(1-p)=10p+2(1-p)

We move all terms to the left:

6p+4(1-p)-(10p+2(1-p))=0

We add all the numbers together, and all the variables

6p+4(-1p+1)-(10p+2(-1p+1))=0

We multiply parentheses

6p-4p-(10p+2(-1p+1))+4=0



We calculate terms in parentheses: -(10p+2(-1p+1)), so:

10p+2(-1p+1)

We multiply parentheses

10p-2p+2

We add all the numbers together, and all the variables

8p+2

Back to the equation:

-(8p+2)



We add all the numbers together, and all the variables

2p-(8p+2)+4=0

We get rid of parentheses

2p-8p-2+4=0

We add all the numbers together, and all the variables

-6p+2=0

We move all terms containing p to the left, all other terms to the right

-6p=-2

p=-2/-6

p=1/3

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