6p+8=2(p-12)/7

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Solution for 6p+8=2(p-12)/7 equation: 



6p+8=2(p-12)/7

We move all terms to the left:

6p+8-(2(p-12)/7)=0

We multiply all the terms by the denominator


6p*7)-(2(p-12)+8*7)=0

We add all the numbers together, and all the variables

6p*7)-(2(p-12)=0

Wy multiply elements

42p^2=0

a = 42; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·42·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{84}=0$

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