6p-1/2(2p-3)=3(1-p)-7/6(p+2)

Solution for 6p-1/2(2p-3)=3(1-p)-7/6(p+2) equation:

6p-1/2(2p-3)=3(1-p)-7/6(p+2)

We move all terms to the left:

6p-1/2(2p-3)-(3(1-p)-7/6(p+2))=0


Domain of the equation: 2(2p-3)!=0

p∈R



Domain of the equation: 6(p+2))!=0

p∈R


We add all the numbers together, and all the variables

6p-1/2(2p-3)-(3(-1p+1)-7/6(p+2))=0

We calculate fractions


6p+(-6pp/(2(2p-3)*6(p+2)))+(-(-3p-14p2)/(2(2p-3)*6(p+2)))=0


We calculate terms in parentheses: +(-6pp/(2(2p-3)*6(p+2))), so:

-6pp/(2(2p-3)*6(p+2))

We multiply all the terms by the denominator


-6pp

Back to the equation:

+(-6pp)



We calculate terms in parentheses: +(-(-3p-14p2)/(2(2p-3)*6(p+2))), so:

-(-3p-14p2)/(2(2p-3)*6(p+2))

We add all the numbers together, and all the variables

-(-3p-14p^2)/(2(2p-3)*6(p+2))

We multiply all the terms by the denominator


-(-3p-14p^2)

We get rid of parentheses

14p^2+3p

Back to the equation:

+(14p^2+3p)


We get rid of parentheses

14p^2+6p-6pp+3p=0

We add all the numbers together, and all the variables

14p^2+9p-6pp=0