6p-3(p+1)+1=2(p-4)+p

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Solution for 6p-3(p+1)+1=2(p-4)+p equation: 



6p-3(p+1)+1=2(p-4)+p

We move all terms to the left:

6p-3(p+1)+1-(2(p-4)+p)=0

We multiply parentheses

6p-3p-(2(p-4)+p)-3+1=0



We calculate terms in parentheses: -(2(p-4)+p), so:

2(p-4)+p

We add all the numbers together, and all the variables

p+2(p-4)

We multiply parentheses

p+2p-8

We add all the numbers together, and all the variables

3p-8

Back to the equation:

-(3p-8)



We add all the numbers together, and all the variables

3p-(3p-8)-2=0

We get rid of parentheses

3p-3p+8-2=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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