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6p^2-12=5p
We move all terms to the left:
6p^2-12-(5p)=0
a = 6; b = -5; c = -12;
Δ = b2-4ac
Δ = -52-4·6·(-12)
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{313}}{2*6}=\frac{5-\sqrt{313}}{12} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{313}}{2*6}=\frac{5+\sqrt{313}}{12} $
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